On 3/27/24 10:58 PM, amirjf nin wrote:
On 9/24/2023 1:57 PM, Tom Roberts wrote:
In our current best theories of electrodynamics, as long as the
apparatus is at rest in a locally-inertial frame, the MMX is
predicted to yield a null result, regardless of how its frame
might be moving.
You say "as long as the apparatus is at rest..." So, what if an MMX
is in low earth orbit? How would that be "at rest"?
You omitted the important caveat: "... at rest in a locally-inertial
frame". The MMX had arms 11 meters long, so the round-trip of light
takes ~ 36 nanoseconds. In 36 ns, Newtonian gravitation predicts it will
fall 0.5*g*t^2 = ~ 5E-15 meters -- that is how far a locally-inertial
frame will move relative to the orbiting apparatus. That is roughly 1E8
times smaller than the wavelength of visible light, and is utterly undetectable.
So for all practical purposes, an MMX in orbit can be considered to be
at rest in a locally inertial frame. Until and unless you can come up
with a detector that can resolve better than 1E-8 wavelength (the MMX
resolved about 0.1 wavelength).
Tom Roberts
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