• Re: Replacement of Cardinality (infinite middle)

    From Moebius@21:1/5 to All on Mon Aug 12 02:08:29 2024
    XPost: sci.logic

    Am 11.08.2024 um 23:38 schrieb Jim Burns:
    On 8/11/2024 2:10 PM, Ross Finlayson wrote:

    How do you see omega

    ω is [...] is for each inductive set,
    the intersection of inductive subsets.

    Indeed! See Halmos' "Naive Set Theory".

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  • From Jim Burns@21:1/5 to Ross Finlayson on Mon Aug 19 00:56:38 2024
    XPost: sci.logic

    On 8/18/2024 5:22 PM, Ross Finlayson wrote:
    On 08/18/2024 10:50 AM, Jim Burns wrote:
    On 8/18/2024 10:17 AM, Ross Finlayson wrote:
    On 08/17/2024 02:12 PM, Jim Burns wrote:

    Lemma 1.
    ⎛ No set B has both
    ⎝ finiteᵖᵍˢˢ order ⟨B,<⟩ and infiniteᵖᵍˢˢ order ⟨B,⩹⟩.

    Definition.
    ⎛ An order ⟨B,<⟩ of B is finiteᵖᵍˢˢ  iff
    ⎜ each non.empty subset S ⊆ B holds
    ⎝ both min[<].S and max[<].S

    A finiteᵖᵍˢˢ set has a finiteᵖᵍˢˢ order.
    An infiniteᵖᵍˢˢ set doesn't have a finiteᵖᵍˢˢ order.

    ℕ ℤ ℚ and ℝ each have infiniteᵖᵍˢˢ orders.
    In the standard order,
    ℕ ℤ ℚ and ℝ are subsets of ℕ ℤ ℚ and ℝ with
    0 or 1 ends.
    Thus, the standard order is infiniteᵖᵍˢˢ.
    Thus, by lemma 1, no non.standard order is finiteᵖᵍˢˢ.

    They do not have any finiteᵖᵍˢˢ order.
    Whatever non.standard order you propose,
    you are proposing an infiniteᵖᵍˢˢ order;
    you are proposing an order with
    some _subset_ with 0 or 1 ends.

    Robinson arithmetic has non.standard models
    with infinite naturals.
    For example, {0}×ℕ ∪ ℚ⁺×ℤ
    ⎛ ⟨p,j⟩ <ꟴ ⟨q,k⟩  ⇔
    ⎝ p < q ∨ (p = q ∧ j < k)

    ⎛ Numbers ⟨p,j⟩ and ⟨q,k⟩ with p<q are
    ⎝ infinitely.far apart.
    ⎛ There are splits between ⟨p,j⟩ and ⟨q,k⟩
    ⎝ with no step from foresplit to hindsplit.
    ( ⟨p,j⟩ is not countable.to ⟨q,k⟩
    ( Not all subsets are 2.ended.

    I'm really beginning to warm up to this idea of
    "finite" and "all orderings are well-orderings"
    being a thing.

    If you're referring to the idea of
    ⎛ for finite,
    ⎝ all orderings are well.ordered both ways
    then I'm pleased to hear
    that you're warming to the idea.
    I wish you much future warming.

    [...] that they're not "immediate" successors,
    thus it's delineated that they're "deferred" successors.

    Standardly, "successor" is "immediate successor".

    We have other ways to say "deferred successor".
    For example, "after".

    Other than an opportunity to enmurken,
    what does the use of "deferred successor" offer?

    So, ordinals less than a limit ordinal are predecessors,

    To review:

    So, with "infinite in the middle", it's just
    that the natural order
    0, infinity - 0,
    1, infinity - 1,
    ...
    has pretty simply two constants "0", "infinity",
    then successors,
    and it has all the models where infinity equates to
    one of 0's successors, and they're finite,
    and a model where it doesn't, that it's infinite.

    This model in which infinity isn't a successor of 0
    by which you mean infinity doesn't come after 0
    how would infinity not coming after 0 work, exactly?

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