If X has decidable equality and negationhttps://ncatlab.org/nlab/show/strongly+extensional+function#examples
of equality is an apartness relation, then
the negation of equality is a (in fact the
unique) decidable tight apartness relation
on X, and any function from X to any set
Y with a tight apartness relation on Y
must be strongly extensional.
In fact, how to constructive mathematics a la Bishop.
I haven't got to the bottom of it, it turns out to be
a long term project in itself, for both theoretical and
technical reasons, but here are few notes and mainly the
references that I have managed to collect.
"How to formalize dependent setoid morphisms?" <https://discourse.rocq-prover.org/t/2759>
To be continued...
-Julio
| Sysop: | Keyop |
|---|---|
| Location: | Huddersfield, West Yorkshire, UK |
| Users: | 715 |
| Nodes: | 16 (2 / 14) |
| Uptime: | 14:32:45 |
| Calls: | 12,101 |
| Calls today: | 1 |
| Files: | 15,004 |
| Messages: | 6,518,029 |