• Dark numbers

    From WM@21:1/5 to All on Tue Apr 8 20:10:58 2025
    The harmonic series diverges. Kempner has shown in 1914 that when all
    terms containing the digit 9 are removed, the serie converges. Here is a
    simple derivation: https://www.hs-augsburg.de/~mueckenh/HI/ p. 15.

    That means that the terms containing 9 diverge. Same is true when all
    terms containing 8 are removed. That means all terms containing 8 and 9 simultaneously diverge.

    We can continue and remove all terms containing 1, 2, 3, 4, 5, 6, 7, 8,
    9, 0 in the denominator without changing this. That means that only the
    terms containing all these digits together constitute the diverging series.

    But that's not the end! We can remove any number, like 2025, and the
    remaining series will converge. For proof use base 2026. This extends to
    every definable number. Therefore the diverging part of the harmonic
    series is constituted only by terms containing a digit sequence of all definable numbers.

    The terms are tiny but that part of the series diverges. This is a proof
    of the huge set of undefinable or dark numbers.

    Regards, WM

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  • From WM@21:1/5 to All on Tue Apr 8 21:24:45 2025
    On 08.04.2025 20:10, WM wrote:
    The harmonic series diverges. Kempner has shown in 1914 that when all
    terms containing the digit 9 are removed, the serie converges. Here is a simple derivation: https://www.hs-augsburg.de/~mueckenh/HI/ p. 15.

    Korrektion
    https://www.hs-augsburg.de/~mueckenh/HI/HI02.PPT p. 15.

    Regards, WM

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