On 7/27/2022 7:20 AM, Timothy Chow wrote:
XGID=-B--ABDAAb--dB---bBdaa-a--:0:0:1:32:0:0:0:0:10
X:Player 2 O:Player 1
Score is X:0 O:0. Unlimited Game +13-14-15-16-17-18------19-20-21-22-23-24-+
| X O X | | O O O O |
| X O X | | O | | | | O |
| | | O |
| | | |
| |BAR| |
| | | |
| O | | X | | O | | X | | O O | | X X X |
| O O X X | | X X X X | +12-11-10--9--8--7-------6--5--4--3--2--1-+
Pip count X: 117 O: 135 X-O: 0-0
Cube: 1
X to play 32
I suppose the idea here is to use the three blots in her home board as
an excuse to run off the eighteen point. Looks sound. Is it better than
simply building the board with 8/4 6/3? Not sure.
If X runs, 61 62 and 63 gives him only one blot to shoot at from the
bar. The other 12 hitting numbers leave at least two and often three
homeboard blots after a hit. And if missed X is well poised to easily
win the race.
"Don't volunteer a shot in a holding game" is sage advice. Probably
should be "Don't volunteer a shot in a holding game unless you're almost
gin if missed and you have lots of counterplay if you are."
So, I'll pay now with 18/13.
--- SoupGate-Win32 v1.05
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