• Anyone up for a EM WLC?

    From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Fri Feb 11 17:26:58 2022
    Nan

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  • From nigel@21:1/5 to All on Mon Feb 14 12:36:26 2022
    王乾懿 Wang Qianyi (Nan) wrote:

    Nan

    I don't think it should be a WLC but, since I've just done a major reconciliation exercise on my EM history, I might be up for a little
    friendly competition after the WLC proper has ended.

    What format are you proposing?

    Do you have the time/inclination to score it?

    Evil Nigel

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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Mon Feb 14 05:00:11 2022
    I have time to invest in predictions as this year has produced some good actual results.

    The original purpose of UK LOTTO 659 was to pick out the seeded predictors. This year's performance was within my expectations, especially for MJ, and according to my Fibonacci series calculation, 4 out of 9 players could already be profitable by
    prediction.
    1. MJ 22300
    2. Nigel 2020
    2. Leela 2020
    2. Random 2020

    https://groups.google.com/g/rec.gambling.lottery/c/w-1HfetyZqE

    And MJ also scored the second highest score ever with 95 points.

    So the conclusion is: In conclusion, to guarantee most players make profits and win money playing UK hot picks, a wise idea is to stop playing after winning more money.

    It would help to lose more to stop playing after round 5 if no 3 in the top 11, as three players got a 3 in the top 11 all in round 5.

    In that case, if you could afford to lose 165*(1+1+2+3+5)=1980 in 5 rounds, you can give a shoot, and win at least 2020 euro back, and if lucky, with a 4 in the top 11, you could win (4*5*800)-{165*(1+1+2+3+5)}=16000-1980=14020 euro, which is so far the
    best strategy with a maximum guarantee.

    So, using the Fibonacci series calculation to come up with the amount of prize money for each player is what I'm aiming for, and this is very real.

    https://www.national-lottery.co.uk/games/euromillions-hotpicks/about-euromillions-hotpicks


    Euro million Match3 has a relatively attractive prize of €1,500. The only difficulty is to draw out 5 numbers, so at least 40% of the players must be able to predict 3 out of 11 within 5-6 rounds in the first 11 numbers, otherwise the meaning of the
    selection is lost.

    So, each player just needs to predict 11 numbers.

    As for how many rounds to hold, my calculation is as follows.

    If we get a 3 in 11 in round 14, the winning would be:

    (377*1500)-{165*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}=
    565500-162690=402810 euro

    So, I plan to hold 14 rounds. The player who wins the most prize money at the end wins.

    Of course, if any player predicts 3 out of 11 in the 5th round, then his prize will be
    (5*1500)-{165*(1+1+2+3+5)}=7500-1980=5520.

    So, this player's score is 5520 points.

    Nan

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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Mon Feb 14 05:04:55 2022
    If a player wins a prize, his round will be reverted to the first round, the For example, if player A wins 5520 points in round 5, because 3 out of 11 numbers are drawn, then round 6 is round 1 for this player.

    The sequence of Fibonacci series play for rounds 1-14 is as follows. 1,1,2,3,5,8,13,21,34,55,89,144,233,377

    Nan

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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Mon Feb 14 05:16:03 2022
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon that there should be a relevant
    formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize.
    Players who win rounds 6-11, although the prize money is high, should divide the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final score is divided by 100.

    What do you guys think?

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  • From Marmaduke Jinks@21:1/5 to All on Mon Feb 14 15:27:44 2022
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds.
    Over time, the amount of investment will skyrocket. Even if a player
    predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize.
    Players who win rounds 6-11, although the prize money is high, should divide the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final score is divided by 100.

    What do you guys think?

    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At �1.50 a go that's �1,454. Pick 3 pays �1,500. I
    think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ

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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Mon Feb 14 17:36:42 2022
    在 2022年2月14日星期一 UTC+8 23:29:07,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan

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  • From Marmaduke Jinks@21:1/5 to All on Tue Feb 15 10:36:59 2022
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    ? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I
    reckon
    that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize.
    Players who win rounds 6-11, although the prize money is high, should
    divide
    the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the
    final
    score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At �1.50 a go that's �1,454. Pick 3 pays �1,500. I
    think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan
    ~~~~

    Ok. So 3 from 11 is 165, at �1.50 that makes an entry �247.50. �1,500 / �247.50 is 6 and a bit.

    You will have 6 goes to make your money back and win a bit.

    MJ

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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 04:59:51 2022
    在 2022年2月15日星期二 UTC+8 18:38:12,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    ? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
    that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
    the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final
    score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan
    ~~~~

    Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.

    You will have 6 goes to make your money back and win a bit.

    MJ
    Nope. if you play with Fibonacci series, it would be another story.

    Fibonacci series
    1,1,2,3,5,8,13,21,34,55,89,144,233,377

    playing times:
    Round 1:1
    Round 2: 1
    Round 3: 3
    ..
    Round 14: 377

    14 ROUNDS

    PLAY UK LOTTO HOT PICKS

    If we get a 3 in 11 in round 6, the winning would be:

    (8*1500)-{165*1.5*(1+1+2+3+5+8)}=
    12000-4950=7050 euro

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:04:30 2022
    在 2022年2月15日星期二 UTC+8 18:38:12,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    ? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
    that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
    the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final
    score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan
    ~~~~

    Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.

    You will have 6 goes to make your money back and win a bit.

    MJ
    Nope. if you play with Fibonacci series, it would be another story.

    Fibonacci series
    1,1,2,3,5,8,13,21,34,55,89,144,233,377

    playing times:
    Round 1:1
    Round 2: 1
    Round 3: 2
    ..
    Round 14: 377

    14 ROUNDS

    PLAY UK LOTTO HOT PICKS

    If we get a 3 in 11 in round 6, the winning would be:

    (8*1500)-{165*1.5*(1+1+2+3+5+8)}=
    12000-4950=7050 euro

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:06:20 2022
    在 2022年2月15日星期二 UTC+8 18:38:12,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    ? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
    that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
    the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final
    score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan
    ~~~~

    Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.

    You will have 6 goes to make your money back and win a bit.

    MJ
    Actually according to my Fibonacci series bet calculation, you have won much for UK HOT PICKS.
    https://groups.google.com/g/rec.gambling.lottery/c/fTcof8Xw3dM

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:03:55 2022
    在 2022年2月14日星期一 UTC+8 21:00:12,<王乾懿 Wang Qianyi (Nan)> 写道:
    I have time to invest in predictions as this year has produced some good actual results.

    The original purpose of UK LOTTO 659 was to pick out the seeded predictors. This year's performance was within my expectations, especially for MJ, and according to my Fibonacci series calculation, 4 out of 9 players could already be profitable by
    prediction.
    1. MJ 22300
    2. Nigel 2020
    2. Leela 2020
    2. Random 2020

    https://groups.google.com/g/rec.gambling.lottery/c/w-1HfetyZqE

    And MJ also scored the second highest score ever with 95 points.

    So the conclusion is: In conclusion, to guarantee most players make profits and win money playing UK hot picks, a wise idea is to stop playing after winning more money.

    It would help to lose more to stop playing after round 5 if no 3 in the top 11, as three players got a 3 in the top 11 all in round 5.

    In that case, if you could afford to lose 165*(1+1+2+3+5)=1980 in 5 rounds, you can give a shoot, and win at least 2020 euro back, and if lucky, with a 4 in the top 11, you could win (4*5*800)-{165*(1+1+2+3+5)}=16000-1980=14020 euro, which is so far
    the best strategy with a maximum guarantee.

    So, using the Fibonacci series calculation to come up with the amount of prize money for each player is what I'm aiming for, and this is very real.

    https://www.national-lottery.co.uk/games/euromillions-hotpicks/about-euromillions-hotpicks


    UPDATE:
    I ignore match3 for EM is 1.5 euro per ticket.
    Euro million Match3 has a relatively attractive prize of €1,500. The only difficulty is to draw out 5 numbers, so at least 40% of the players must be able to predict 3 out of 11 within 5-6 rounds in the first 11 numbers, otherwise the meaning of the
    selection is lost.

    So, each player just needs to predict 11 numbers.

    As for how many rounds to hold, my calculation is as follows.

    If we get a 3 in 11 in round 14, the winning would be:

    (377*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}= 321465 euro

    So, I plan to hold 14 rounds. The player who wins the most prize money at the end wins.

    Of course, if any player predicts 3 out of 11 in the 5th round, then his prize will be
    (5*1500)-{165*1.5*(1+1+2+3+5)}=7500-1980*1.5=4530

    So, this player's score is 5520 points.

    Nan

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:07:59 2022
    在 2022年2月15日星期二 UTC+8 18:38:12,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    ? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
    that there should be a relevant formula to subtract the deduction for investment possibility.

    My initial criteria is as follows:
    Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
    the final score by 10 to get the final score.
    For the winners of rounds 12-14, although the prize money is high, the final
    score is divided by 100.

    What do you guys think?
    ~~

    I'll give it a go if others are. 11 seems low.

    What I do know is this.

    3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.

    MJ
    Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
    Nan
    ~~~~

    Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.

    You will have 6 goes to make your money back and win a bit.

    MJ
    You can play up to 14 rounds, and
    If we get a 3 in 11 in round 14, the winning would be:
    (377*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}= 321465 euro

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:37:47 2022
    Fibonacci series
    1,1,2,3,5,8,13,21,34,55,89,144,233,377

    Playing times:
    Round 1:1
    Round 2: 1
    Round 3: 2
    ..
    Round 14: 377

    14 ROUNDS

    PLAY EM MATCH3~

    If each play gives two sets of 11 numbers to increase the 3 in 11 winning chances, the outcome would be:

    as you can see, the risk is too high and the prize is too less.

    If we get a 3 in 11 in round 1, the winning would be:
    (1500)-{2*165*1.5*1}=495 euro
    If we get a 3 in 11 in round 2, the winning would be: (1*1500)-{2*165*1.5*(1+1)}=510 euro
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{2*165*1.5*(1+1+2)}= 1020 euro
    If we get a 3 in 11 in round 4, the winning would be: (3*1500)-{2*165*1.5*(1+1+2+3)}= 1035 euro
    If we get a 3 in 11 in round 5, the winning would be: (5*1500)-{2*165*1.5*(1+1+2+3+5)}= 1560 euro
    If we get a 3 in 11 in round 6, the winning would be: (8*1500)-{2*165*1.5*(1+1+2+3+5+8)}=11010 euro
    If we get a 3 in 11 in round 7, the winning would be: (13*1500)-{2*165*1.5*(1+1+2+3+5+8+13)}=3165 euro
    If we get a 3 in 11 in round 8, the winning would be: (21*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21)}=4770 euro
    If we get a 3 in 11 in round 9, the winning would be: (34*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21+34)}=7440 euro
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21+34+55)}=11715 euro
    If we get a 3 in 11 in round 11, the winning would be: (89*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21+34+55+89)}=18660 euro
    If we get a 3 in 11 in round 12, the winning would be: (144*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144)}=29880 euro
    If we get a 3 in 11 in round 13, the winning would be: (233*1500)-{2*165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233)}= 48045 euro

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:25:46 2022
    Fibonacci series
    1,1,2,3,5,8,13,21,34,55,89,144,233,377

    Playing times:
    Round 1:1
    Round 2: 1
    Round 3: 2
    ..
    Round 14: 377

    14 ROUNDS

    PLAY EM MATCH3~

    If we get a 3 in 11 in round 1, the winning would be:
    (1500)-{165*1.5*1}=1252.5 euro
    If we get a 3 in 11 in round 2, the winning would be: (1*1500)-{165*1.5*(1+1)}=1005 euro
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
    If we get a 3 in 11 in round 4, the winning would be: (3*1500)-{165*1.5*(1+1+2+3)}= 2767.5 euro
    If we get a 3 in 11 in round 5, the winning would be: (5*1500)-{165*1.5*(1+1+2+3+5)}= 4530euro
    If we get a 3 in 11 in round 6, the winning would be: (8*1500)-{165*1.5*(1+1+2+3+5+8)}=12000-4950=7050 euro
    If we get a 3 in 11 in round 7, the winning would be: (13*1500)-{165*1.5*(1+1+2+3+5+8+13)}=11332.5 euro
    If we get a 3 in 11 in round 8, the winning would be: (21*1500)-{165*1.5*(1+1+2+3+5+8+13+21)}=18135 euro
    If we get a 3 in 11 in round 9, the winning would be: (34*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34)}=29220 euro
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro
    If we get a 3 in 11 in round 11, the winning would be: (89*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89)}=76080 euro
    If we get a 3 in 11 in round 12, the winning would be: (144*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144)}=122940 euro
    If we get a 3 in 11 in round 13, the winning would be: (233*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233)}= 198772.5 euro
    If we get a 3 in 11 in round 14, the winning would be: (377*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}= 321465 euro

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 05:55:25 2022
    I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at round 7 with a 3 in top 11.
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
    If MJ stops playing, he would altogether win 2010 euro.


    Frank and Nan both won at round 10, winning
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro

    Frank:-
    46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
    Nan
    26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ

    You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.

    Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.

    And based on such standard, the final score would be:

    1. Frank ; Nan 4710.75 POINTS
    2. MJ 2020 POINTS

    --- SoupGate-Win32 v1.05
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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 06:02:58 2022
    So the standard for scoring would be (draft)

    Round 1: 252.5 POINTS
    Round 2: 1005 POINTS
    Round 3: 2010 POINTS
    Round 4: 2767.5 POINTS
    Round 5: 4530POINTS

    Round 6: 705 POINTS
    Round 7: 1133.25 POINTS
    Round 8: 1813.5 POINTS
    Round 9: 2922 POINTS
    Round 10 :4710.75 POINTS
    Round 11: 7608 POINTS

    Round 12: 1229.40 POINTS
    Round 13: 1987.725 POINTS
    Round 14: 3214. 65 POINTS

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 06:25:10 2022
    I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at round 7 with a 3 in top 11.
    https://groups.google.com/g/rec.gambling.lottery/c/B3x5om0whI8/m/E6BL-1ZHGwAJ If we get a 3 in 11 in round 7, the winning would be: (13*1500)-{165*1.5*(1+1+2+3+5+8+13)}=11332.5 euro
    If MJ stops playing, he would altogether win 11332.5 euro.


    Frank and Nan both won at round 10, winning
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro

    Frank:-
    46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
    Nan
    26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ

    You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.

    Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.

    And based on such standard, the final score would be:


    1. MJ 11332 POINTS
    2. Frank ; Nan 4710.75 POINTS

    More points given as they played more rounds and taken more risk of losing.

    --- SoupGate-Win32 v1.05
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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 06:20:53 2022
    In WLC 2020, Jinks, NN, Frank, and Nan participated, and three of them have finally won, accounting for 75%.

    This is so far the most guaranteed and best prize return strategy I could think of.

    The only issue is that the investment would get way beyond affordability for actual play, soon after Round 5.

    Investment needed:

    Round 1: 247.5
    Round 2: 495 euro
    Round 3: 990 euro
    3 Rounds! The quickest record made by MJ for WLC EURO MILLION 2020
    Round 4: 1732.5 euro
    Round 5: 2970 euro
    Most players stop here if lose all.
    Round 6: 4950 euro
    Round 7: 8167.5 euro
    Round 8: 13365 euro
    Round 9: 21780 euro
    Round 10: 35392.5 euro
    Round 11: 57420 euro
    Very few can insist here but the chance increases to 75% according to WLC 2020. Round 12: 93060 euro
    Round 13: 150727.5 euro
    Round 14 244035 euro
    IMPOSSIBLE FOR 99%.



    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 06:26:32 2022
    In WLC EM 2020, Jinks, NN, Frank, and Nan participated, and three of them have finally won, accounting for 75%.

    This is so far the most guaranteed and best prize return strategy I could think of.

    The only issue is that the investment would get way beyond affordability for actual play, soon after Round 5.

    Investment needed:

    Round 1: 247.5
    Round 2: 495 euro
    Round 3: 990 euro
    Round 4: 1732.5 euro
    Round 5: 2970 euro
    Most players stop here if losing all.
    Round 6: 4950 euro
    Round 7: 8167.5 euro
    7 Rounds! The quickest record made by MJ for WLC EURO MILLION 2020
    Round 8: 13365 euro
    Round 9: 21780 euro
    Round 10: 35392.5 euro
    Nan and Frank made it in round 10.
    Round 11: 57420 euro
    Very few can insist here but the chance increases to 75% according to WLC 2020. Round 12: 93060 euro
    Round 13: 150727.5 euro
    Round 14 244035 euro
    IMPOSSIBLE FOR 99%.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 06:39:55 2022
    So the standard for scoring would be (draft)

    Original points with deduction

    Round 1: 252.5 POINTS
    Round 2: 1005 POINTS
    Round 3: 2010 POINTS
    Round 4: 2767.5 POINTS
    Round 5: 4530 POINTS

    Round 6: 7050 POINTS
    Round 7: 11332.5 POINTS
    Round 8: 18135 POINTS
    Round 9: 29220 POINTS
    Round 10 :47107.5 POINTS
    Round 11: 76080 POINTS

    Round 12: 122940 POINTS
    Round 13: 198772.5 POINTS
    Round 14: 321465 POINTS

    So the standard for scoring would be (draft) after investment risk deduction Round 6-11 divide all points by 10 and round 12-14 divide all points by 100.

    Round 1: 252.5 POINTS
    Round 2: 1005 POINTS
    Round 3: 2010 POINTS
    Round 4: 2767.5 POINTS
    Round 5: 4530POINTS

    Round 6: 705 POINTS
    Round 7: 1133.25 POINTS
    Round 8: 1813.5 POINTS
    Round 9: 2922 POINTS
    Round 10 :4710.75 POINTS
    Round 11: 7608 POINTS

    Round 12: 1229.40 POINTS
    Round 13: 1987.725 POINTS
    Round 14: 3214. 65 POINTS

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Marmaduke Jinks@21:1/5 to All on Tue Feb 15 16:41:13 2022
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at >round 7 with a 3 in top 11.
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
    If MJ stops playing, he would altogether win 2010 euro.


    Frank and Nan both won at round 10, winning
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro

    Frank:-
    46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
    Nan
    26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ

    You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.

    Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.

    And based on such standard, the final score would be:

    1. Frank ; Nan 4710.75 POINTS
    2. MJ 2020 POINTS

    You missed my point that after 7 draws of Euromillions it's far too late.

    I'll leave you to your calculations.

    MJ "There's no more money" ;-)

    --- SoupGate-Win32 v1.05
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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 19:09:36 2022
    If you win at round 7, and stop playing, you will always be the winner.
    The point is:
    1. if someone has enough money to support to play until at least round 7.
    2. if he could stop playing and keep the money in pocket.
    3. if he could buy some many tickets in UK.
    4. if he has enough initial money to start playing.
    5. if he could make a 3 in 11 in 7 rounds, so far the chances among 4 players is 25% due to WLC EM 2020 statistics.
    Nan

    --- SoupGate-Win32 v1.05
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  • From =?UTF-8?B?546L5Lm+5oe/IFdhbmcgUWlhb@21:1/5 to All on Tue Feb 15 19:04:20 2022
    在 2022年2月16日星期三 UTC+8 00:42:25,<Marmaduke Jinks> 写道:
    "??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
    I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at >round 7 with a 3 in top 11.
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
    If MJ stops playing, he would altogether win 2010 euro.


    Frank and Nan both won at round 10, winning
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro

    Frank:-
    46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
    Nan
    26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ

    You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.

    Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.

    And based on such standard, the final score would be:

    1. Frank ; Nan 4710.75 POINTS
    2. MJ 2020 POINTS

    You missed my point that after 7 draws of Euromillions it's far too late.

    I'll leave you to your calculations.

    MJ "There's no more money" ;-)

    Fibonacci series
    1,1,2,3,5,8,13,21,34,55,89,144,233,377

    Playing times:
    Round 1:1
    Round 2: 1
    Round 3: 2
    ..
    Round 14: 377

    14 ROUNDS

    PLAY EM MATCH3~

    If we get a 3 in 11 in round 1, the winning would be:
    (1500)-{165*1.5*1}=1252.5 euro
    If we get a 3 in 11 in round 2, the winning would be: (1*1500)-{165*1.5*(1+1)}=1005 euro
    If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
    If we get a 3 in 11 in round 4, the winning would be: (3*1500)-{165*1.5*(1+1+2+3)}= 2767.5 euro
    If we get a 3 in 11 in round 5, the winning would be: (5*1500)-{165*1.5*(1+1+2+3+5)}= 4530euro
    If we get a 3 in 11 in round 6, the winning would be: (8*1500)-{165*1.5*(1+1+2+3+5+8)}=12000-4950=7050 euro
    If we get a 3 in 11 in round 7, the winning would be: (13*1500)-{165*1.5*(1+1+2+3+5+8+13)}=11332.5 euro
    If we get a 3 in 11 in round 8, the winning would be: (21*1500)-{165*1.5*(1+1+2+3+5+8+13+21)}=18135 euro
    If we get a 3 in 11 in round 9, the winning would be: (34*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34)}=29220 euro
    If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro
    If we get a 3 in 11 in round 11, the winning would be: (89*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89)}=76080 euro
    If we get a 3 in 11 in round 12, the winning would be: (144*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144)}=122940 euro
    If we get a 3 in 11 in round 13, the winning would be: (233*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233)}= 198772.5 euro
    If we get a 3 in 11 in round 14, the winning would be: (377*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}= 321465 euro

    Anyone wishing to win has to have enough money. After 7 rounds, it would need 13365 euro for round 8, etc...

    Based on past performance, the quickest round is round 7, so 8167.5 euro is needed for winning 11332.5 euro.

    (13*1500)-{165*1.5*(1+1+2+3+5+8+13)}=11332.5 euro

    Investment needed:

    Round 1: 247.5
    Round 2: 495 euro
    Round 3: 990 euro
    Round 4: 1732.5 euro
    Round 5: 2970 euro
    Most players stop here if losing all.
    Round 6: 4950 euro
    Round 7: 8167.5 euro
    7 Rounds! The quickest record made by MJ for WLC EURO MILLION 2020
    Round 8: 13365 euro
    Round 9: 21780 euro
    Round 10: 35392.5 euro
    Nan and Frank made it in round 10.
    Round 11: 57420 euro
    Very few can insist here but the chance increases to 75% according to WLC 2020. Round 12: 93060 euro
    Round 13: 150727.5 euro
    Round 14 244035 euro
    IMPOSSIBLE FOR 99%.

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    * Origin: fsxNet Usenet Gateway (21:1/5)