Nan
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the final score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJ
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...Wouldn't keep consistency be a difficult task? You only need to win once and collect money.
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I
reckon
that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize.
Players who win rounds 6-11, although the prize money is high, should
divide
the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the
final
score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At �1.50 a go that's �1,454. Pick 3 pays �1,500. I
think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJ
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...Nope. if you play with Fibonacci series, it would be another story.
? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the final
score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJWouldn't keep consistency be a difficult task? You only need to win once and collect money.
Nan
~~~~
Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.
You will have 6 goes to make your money back and win a bit.
MJ
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...Nope. if you play with Fibonacci series, it would be another story.
? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the final
score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJWouldn't keep consistency be a difficult task? You only need to win once and collect money.
Nan
~~~~
Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.
You will have 6 goes to make your money back and win a bit.
MJ
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...Actually according to my Fibonacci series bet calculation, you have won much for UK HOT PICKS.
? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the final
score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJWouldn't keep consistency be a difficult task? You only need to win once and collect money.
Nan
~~~~
Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.
You will have 6 goes to make your money back and win a bit.
MJ
I have time to invest in predictions as this year has produced some good actual results.prediction.
The original purpose of UK LOTTO 659 was to pick out the seeded predictors. This year's performance was within my expectations, especially for MJ, and according to my Fibonacci series calculation, 4 out of 9 players could already be profitable by
1. MJ 22300the best strategy with a maximum guarantee.
2. Nigel 2020
2. Leela 2020
2. Random 2020
https://groups.google.com/g/rec.gambling.lottery/c/w-1HfetyZqE
And MJ also scored the second highest score ever with 95 points.
So the conclusion is: In conclusion, to guarantee most players make profits and win money playing UK hot picks, a wise idea is to stop playing after winning more money.
It would help to lose more to stop playing after round 5 if no 3 in the top 11, as three players got a 3 in the top 11 all in round 5.
In that case, if you could afford to lose 165*(1+1+2+3+5)=1980 in 5 rounds, you can give a shoot, and win at least 2020 euro back, and if lucky, with a 4 in the top 11, you could win (4*5*800)-{165*(1+1+2+3+5)}=16000-1980=14020 euro, which is so far
So, using the Fibonacci series calculation to come up with the amount of prize money for each player is what I'm aiming for, and this is very real.
https://www.national-lottery.co.uk/games/euromillions-hotpicks/about-euromillions-hotpicks
Euro million Match3 has a relatively attractive prize of €1,500. The only difficulty is to draw out 5 numbers, so at least 40% of the players must be able to predict 3 out of 11 within 5-6 rounds in the first 11 numbers, otherwise the meaning of theselection is lost.
So, each player just needs to predict 11 numbers.
As for how many rounds to hold, my calculation is as follows.
If we get a 3 in 11 in round 14, the winning would be:
(377*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55+89+144+233+377)}= 321465 euro
So, I plan to hold 14 rounds. The player who wins the most prize money at the end wins.
Of course, if any player predicts 3 out of 11 in the 5th round, then his prize will be
(5*1500)-{165*1.5*(1+1+2+3+5)}=7500-1980*1.5=4530
So, this player's score is 5520 points.
Nan
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...You can play up to 14 rounds, and
? 2022?2?14???? UTC+8 23:29:07,<Marmaduke Jinks> ??:
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
In fact, this rubric ignores the ability to actually invest in 14 rounds. Over time, the amount of investment will skyrocket. Even if a player predicted 3 out of 11 in round 14, earning a high score of 402,810, I reckon
that there should be a relevant formula to subtract the deduction for investment possibility.
My initial criteria is as follows:
Winners of rounds 1-5 are assessed a score based on the actual prize. Players who win rounds 6-11, although the prize money is high, should divide
the final score by 10 to get the final score.
For the winners of rounds 12-14, although the prize money is high, the final
score is divided by 100.
What do you guys think?
~~
I'll give it a go if others are. 11 seems low.
What I do know is this.
3 from 19 is 969. At £1.50 a go that's £1,454. Pick 3 pays £1,500. I think if you can consistently get 3 from 19 then you'd be a winner. It's finessing the number of numbers that you choose.
MJWouldn't keep consistency be a difficult task? You only need to win once and collect money.
Nan
~~~~
Ok. So 3 from 11 is 165, at £1.50 that makes an entry £247.50. £1,500 / £247.50 is 6 and a bit.
You will have 6 goes to make your money back and win a bit.
MJ
I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at >round 7 with a 3 in top 11.
If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
If MJ stops playing, he would altogether win 2010 euro.
Frank and Nan both won at round 10, winning
If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro
Frank:-
46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
Nan
26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ
You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.
Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.
And based on such standard, the final score would be:
1. Frank ; Nan 4710.75 POINTS
2. MJ 2020 POINTS
"??? Wang Qianyi (Nan)" <[email protected]> wrote in message news:[email protected]...
I searched WLC EURO MILLION 2020, and the quickest winner is MJ, winning at >round 7 with a 3 in top 11.
If we get a 3 in 11 in round 3, the winning would be: (2*1500)-{165*1.5*(1+1+2)}= 2010 euro
If MJ stops playing, he would altogether win 2010 euro.
Frank and Nan both won at round 10, winning
If we get a 3 in 11 in round 10, the winning would be: (55*1500)-{165*1.5*(1+1+2+3+5+8+13+21+34+55)}=47107.5 euro
Frank:-
46,39,34,33,30,24,23*,22*,21,20*,18,13,11*,09,02,44,43,26,14,45
Nan
26 20* 09 46 24 08* 04BB 37 13 50 22* 02 33 34 10 32 43 06 38 35 https://groups.google.com/g/rec.gambling.lottery/c/VmHhsjyTVyg/m/JooAb68kHAAJ
You see, it would be unfair to rank Frank and Nan as the winners, even if they won more money as the money invested skyrocketed.
Therefore, I propose to divide total points (prizes) by 10 times for round 6-11, and by 100 times for round 12-14.
And based on such standard, the final score would be:
1. Frank ; Nan 4710.75 POINTS
2. MJ 2020 POINTS
You missed my point that after 7 draws of Euromillions it's far too late.
I'll leave you to your calculations.
MJ "There's no more money" ;-)
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