• Re: Google [x86utm operating system]

    From Mr Flibble@21:1/5 to olcott on Fri Aug 8 16:18:42 2025
    On Fri, 08 Aug 2025 11:08:33 -0500, olcott wrote:

    Google [x86utm operating system]
    provides an excellent overview of my work.

    The "x86utm operating system" is a project primarily focused on
    exploring the philosophical and practical implications of the Halting
    Problem in computer science, specifically at a lower level of
    abstraction than traditional proofs.

    Key aspects Emulation-based: It is built on an x86 emulator, allowing it
    to simulate the execution of other programs, like C functions, at a low
    level (machine language).

    Halting Problem Research: The x86utm operating system acts as a testbed
    for studying the Halting Problem, particularly for analyzing the
    behavior of programs with paradoxical relationships to their simulators (e.g., programs designed to do the opposite of what a halting program
    would report).

    Termination Analysis: The project focuses on "simulating termination analyzers" (like function HHH mentioned in search results) that can
    observe and detect non-halting behavior patterns in simulated programs,
    like infinite loops or recursion, and then abort the simulation,
    reporting that the program would not halt.

    Relevance: The x86utm project contributes to a deeper understanding of
    the Halting Problem by examining it through concrete examples and the behavior of programs within an emulated environment.

    In essence The x86utm operating system is a specialized environment for investigating the nuances of the Halting Problem. It's not a
    general-purpose operating system in the sense of Windows or Linux, but
    rather a tool to explore fundamental computer science concepts at a
    concrete level, using emulation and termination analysis to observe and understand program behavior, particularly in the context of halting and non-halting computations.

    Your work? You mean your 22 years of time wasting? x86utm has nothing to
    do with the Halting Problem as it only consists of a partial decider
    rather than the total decider required for the Halting Problem.

    /Flibble

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  • From Mikko@21:1/5 to Mr Flibble on Sun Aug 10 10:58:46 2025
    On 2025-08-08 16:18:42 +0000, Mr Flibble said:

    On Fri, 08 Aug 2025 11:08:33 -0500, olcott wrote:

    Google [x86utm operating system]
    provides an excellent overview of my work.

    The "x86utm operating system" is a project primarily focused on
    exploring the philosophical and practical implications of the Halting
    Problem in computer science, specifically at a lower level of
    abstraction than traditional proofs.

    Key aspects Emulation-based: It is built on an x86 emulator, allowing it
    to simulate the execution of other programs, like C functions, at a low
    level (machine language).

    Halting Problem Research: The x86utm operating system acts as a testbed
    for studying the Halting Problem, particularly for analyzing the
    behavior of programs with paradoxical relationships to their simulators
    (e.g., programs designed to do the opposite of what a halting program
    would report).

    Termination Analysis: The project focuses on "simulating termination
    analyzers" (like function HHH mentioned in search results) that can
    observe and detect non-halting behavior patterns in simulated programs,
    like infinite loops or recursion, and then abort the simulation,
    reporting that the program would not halt.

    Relevance: The x86utm project contributes to a deeper understanding of
    the Halting Problem by examining it through concrete examples and the
    behavior of programs within an emulated environment.

    In essence The x86utm operating system is a specialized environment for
    investigating the nuances of the Halting Problem. It's not a
    general-purpose operating system in the sense of Windows or Linux, but
    rather a tool to explore fundamental computer science concepts at a
    concrete level, using emulation and termination analysis to observe and
    understand program behavior, particularly in the context of halting and
    non-halting computations.

    Your work? You mean your 22 years of time wasting? x86utm has nothing to
    do with the Halting Problem as it only consists of a partial decider
    rather than the total decider required for the Halting Problem.

    It does illustrate the insolvability of the halting problem, in particular
    the failure of the simulation approach, which might look promising.

    --
    Mikko

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  • From Mr Flibble@21:1/5 to olcott on Sun Aug 10 16:22:41 2025
    On Sun, 10 Aug 2025 09:15:12 -0500, olcott wrote:

    On 8/10/2025 2:58 AM, Mikko wrote:
    On 2025-08-08 16:18:42 +0000, Mr Flibble said:

    On Fri, 08 Aug 2025 11:08:33 -0500, olcott wrote:

    Google [x86utm operating system]
    provides an excellent overview of my work.

    The "x86utm operating system" is a project primarily focused on
    exploring the philosophical and practical implications of the Halting
    Problem in computer science, specifically at a lower level of
    abstraction than traditional proofs.

    Key aspects Emulation-based: It is built on an x86 emulator, allowing
    it to simulate the execution of other programs, like C functions, at
    a low level (machine language).

    Halting Problem Research: The x86utm operating system acts as a
    testbed for studying the Halting Problem, particularly for analyzing
    the behavior of programs with paradoxical relationships to their
    simulators (e.g., programs designed to do the opposite of what a
    halting program would report).

    Termination Analysis: The project focuses on "simulating termination
    analyzers" (like function HHH mentioned in search results) that can
    observe and detect non-halting behavior patterns in simulated
    programs, like infinite loops or recursion, and then abort the
    simulation, reporting that the program would not halt.

    Relevance: The x86utm project contributes to a deeper understanding
    of the Halting Problem by examining it through concrete examples and
    the behavior of programs within an emulated environment.

    In essence The x86utm operating system is a specialized environment
    for investigating the nuances of the Halting Problem. It's not a
    general-purpose operating system in the sense of Windows or Linux,
    but rather a tool to explore fundamental computer science concepts at
    a concrete level, using emulation and termination analysis to observe
    and understand program behavior, particularly in the context of
    halting and non-halting computations.

    Your work? You mean your 22 years of time wasting? x86utm has nothing
    to do with the Halting Problem as it only consists of a partial
    decider rather than the total decider required for the Halting
    Problem.

    It does illustrate the insolvability of the halting problem, in
    particular the failure of the simulation approach, which might look
    promising.


    Claude AI proved why HHH(DD)==0 is correct in terms that any expert C programmer can understand. https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    On Sun, 10 Aug 2025 09:30:11 -0500, olcott wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that any expert C programmer can understand. https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    I am an expert C programmer which is why I understand that DD() halts,
    HHH(DD) reports non-halting and thus is not a halt decider over DD as it
    gets the answer wrong -- thus you have not refuted any Halting Problem
    proofs and have thus wasted the last 22 years.

    /Flibble

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  • From Mikko@21:1/5 to olcott on Mon Aug 11 09:44:15 2025
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:
    On 2025-08-08 16:18:42 +0000, Mr Flibble said:

    On Fri, 08 Aug 2025 11:08:33 -0500, olcott wrote:

    Google [x86utm operating system]
    provides an excellent overview of my work.

    The "x86utm operating system" is a project primarily focused on
    exploring the philosophical and practical implications of the Halting
    Problem in computer science, specifically at a lower level of
    abstraction than traditional proofs.

    Key aspects Emulation-based: It is built on an x86 emulator, allowing it >>>> to simulate the execution of other programs, like C functions, at a low >>>> level (machine language).

    Halting Problem Research: The x86utm operating system acts as a testbed >>>> for studying the Halting Problem, particularly for analyzing the
    behavior of programs with paradoxical relationships to their simulators >>>> (e.g., programs designed to do the opposite of what a halting program
    would report).

    Termination Analysis: The project focuses on "simulating termination
    analyzers" (like function HHH mentioned in search results) that can
    observe and detect non-halting behavior patterns in simulated programs, >>>> like infinite loops or recursion, and then abort the simulation,
    reporting that the program would not halt.

    Relevance: The x86utm project contributes to a deeper understanding of >>>> the Halting Problem by examining it through concrete examples and the
    behavior of programs within an emulated environment.

    In essence The x86utm operating system is a specialized environment for >>>> investigating the nuances of the Halting Problem. It's not a
    general-purpose operating system in the sense of Windows or Linux, but >>>> rather a tool to explore fundamental computer science concepts at a
    concrete level, using emulation and termination analysis to observe and >>>> understand program behavior, particularly in the context of halting and >>>> non-halting computations.

    Your work? You mean your 22 years of time wasting? x86utm has nothing to >>> do with the Halting Problem as it only consists of a partial decider
    rather than the total decider required for the Halting Problem.

    It does illustrate the insolvability of the halting problem, in particular >> the failure of the simulation approach, which might look promising.

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand. https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.

    Apparently you don't understand what Claude AI said as you can only
    refer to it but cannot prove the same.

    Also
    https://philpapers.org/archive/OLCHPS.pdf

    As soon as you understand that the above page is
    entirely correct we can proceed to the last step
    of my proof.

    That paper is not entirely correct. It starts with an ill-posed question
    "What value should HHH(DD) correctly return?" where the exact meanings
    of "should" and "correctly" are not defined and cannot be inferred from
    the context.

    Later in the text there is the pharase "according to the specification"
    that does not identify any specification.

    In the "Answer" section there is the phrase "correctly identifies" where
    the norm for correctness is not identified. What is correct by one norm
    is incorrect by another norm. In this case the answer claimed "correct"
    is incorrect by the meanings of "termination analyzer" and "halting
    decider".

    That you hadn't noticed any error doesn't mean that there are none.

    Besidss, the text should have a title. And numbers in the text should
    be set with upper case digits.

    --
    Mikko

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 16:46:28 2025
    On 11/08/2025 16:21, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:

    <snip>


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to
    be "wrong"?

    Good question.

    The halting problem specification requires a halt
    decider

    On the contrary, the halting problem demonstrates that such a
    decider cannot be built. Turing no more requires you to construct
    a halt decider than Zeno requires you to train a tortoise.

    <snip>

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From joes@21:1/5 to All on Mon Aug 11 15:49:20 2025
    Am Mon, 11 Aug 2025 10:21:50 -0500 schrieb olcott:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:
    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:
    On 8/10/2025 2:58 AM, Mikko wrote:

    Irrelevant as long as the meaning of "correct" is not 'as required by
    the halting problem specification'.

    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be
    "wrong"?

    The halting problem specification requires a halt decider to report on
    the behavior of the underlying Turing machine under the false assumption
    that input DD correctly simulated by halt decider HHH must have the same behavior as the directly executed DD().
    When I prove otherwise people here go on and on and on making sure to
    ignore this proof for months and months over years and years.
    When they finally pay attention they say this proves that the simulation
    is wrong.
    When I prove that the simulation is correct they baselessly disagree. We
    fail to make progress because people will not look at the proof that the simulation is correct.

    You have no proof that the simulation is correct other than redefining it.

    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.

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  • From joes@21:1/5 to All on Mon Aug 11 16:23:00 2025
    Am Mon, 11 Aug 2025 11:12:03 -0500 schrieb olcott:
    On 8/11/2025 11:05 AM, dbush wrote:
    On 8/11/2025 12:04 PM, olcott wrote:
    On 8/11/2025 10:49 AM, dbush wrote:
    On 8/11/2025 11:48 AM, olcott wrote:
    On 8/11/2025 10:43 AM, dbush wrote:

    i.e. it doesn't correctly simulate its input.

    *Counter-factual*

    You cannot show that DD emulated by HH according to the definition
    of the x86 language

    Does not occur as you have admitted on the record:

    No that is merely your attention deficit disorder failing to pay
    attention to the definition of HHH
    Simulating Termination Analyzer HHH correctly simulates its input
    until:

    i.e. it doesn't correctly simulate its input

    If that was true then the exact error could be found.

    The error is that it can't simulate past itself and gets bogged down
    in recursion.

    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 17:18:24 2025
    On 11/08/2025 16:55, olcott wrote:
    On 8/11/2025 10:46 AM, Richard Heathfield wrote:
    On 11/08/2025 16:21, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:

    <snip>


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to
    be "wrong"?

    Good question.

    The halting problem specification requires a halt
    decider

    On the contrary, the halting problem demonstrates that such a
    decider cannot be built. Turing no more requires you to
    construct a halt decider than Zeno requires you to train a
    tortoise.

    <snip>


    Yes when you assume that I am wrong

    It's not an assumption. I have a proof.

    and then make
    sure to ignore what I said

    When you say something worth reading, let me know. It hasn't
    happened yet.

    To date, all you've written are assertions masquerading as proofs
    - proofs that hold less water than a colander. You have an
    emulator that fails to emulate, a single-stepper that ignores 75%
    of what it's supposed to be single-stepping, a master's degree in
    rude buggeriness, and a complete inability to tell the difference
    between a thought experiment and an engineering project. You're
    the man who thought if only Icarus had used better glue.

    the false assumption
    cannot be shown to be false.

    Feel free to try. If you make a serious stab, I'll listen. But if
    you just say "first you must accept this list of falsehoods", I
    won't. You don't have a licence to demand that people accept
    bullshit in place of logic.

    Good job you used zero reasoning to affirm a false
    assumption. You know that this false assumption is
    true entirely on the basis of an incorrect guess.

    The only assumption I'm making is that you are right - Icarus can
    fly higher still, and a universal halt decider can be built.
    Having made that assumption, I can walk in Turing's footprints
    and derive a contradiction that proves the assumption to be
    false. No guessing involved.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From joes@21:1/5 to All on Mon Aug 11 16:35:00 2025
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than redefining
    it.

    The categorical impossibility of finding a specific an error is this
    proof.

    You cannot show that DD emulated by HH according to the definition of
    the x86 language can possibly reach its own correctly emulated "ret" instruction because it cannot.
    That is the error.

    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 17:42:47 2025
    On 11/08/2025 17:29, olcott wrote:

    <snip>


    I have proven that DD correctly simulated by HHH

    No, you haven't. You have asserted that the simulation is
    correct, but we all know that it derives a different result from
    that produced by direct execution, and therefore we all know that
    the simulation is not correct. We also know that the simulator
    cannot (and therefore fails to) simulate the DD code that calls
    it and the DD code that follows that call.

    cannot possibly reach its own "return" statement
    final halt state and you baselessly disagree.

    It's not baseless. I've explained the basis many times (see above
    for another exposition!), and you've tried to handwave it away
    many times. It hasn't worked.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Heathfield@21:1/5 to dbush on Mon Aug 11 18:16:09 2025
    On 11/08/2025 17:35, dbush wrote:
    On 8/11/2025 12:31 PM, olcott wrote:
    On 8/11/2025 11:13 AM, dbush wrote:
    On 8/11/2025 12:12 PM, olcott wrote:
    On 8/11/2025 11:05 AM, dbush wrote:
    On 8/11/2025 12:04 PM, olcott wrote:
    On 8/11/2025 10:49 AM, dbush wrote:
    On 8/11/2025 11:48 AM, olcott wrote:
    On 8/11/2025 10:43 AM, dbush wrote:

    i.e. it doesn't correctly simulate its input.


    *Counter-factual*

    _DD()
    [00002162] 55         push ebp
    [00002163] 8bec       mov ebp,esp
    [00002165] 51         push ecx
    [00002166] 6862210000 push 00002162 // push DD
    [0000216b] e862f4ffff call 000015d2 // call HHH
    [00002170] 83c404     add esp,+04
    [00002173] 8945fc     mov [ebp-04],eax
    [00002176] 837dfc00   cmp dword [ebp-04],+00
    [0000217a] 7402       jz 0000217e
    [0000217c] ebfe       jmp 0000217c
    [0000217e] 8b45fc     mov eax,[ebp-04]
    [00002181] 8be5       mov esp,ebp
    [00002183] 5d         pop ebp
    [00002184] c3         et
    Size in bytes:(0035) [00002184]

    You cannot show that DD emulated by HH according
    to the definition of the x86 language


    Does not occur as you have admitted on the record:


    No that is merely your attention deficit disorder failing
    to pay attention to the definition of HHH

    Simulating Termination Analyzer HHH correctly simulates its
    input until:

    i.e. it doesn't correctly simulate its input


    If that was true then the exact error could be found.

    The error is that HHH aborts in violation of the x86 language
    spec.

    *That is not an error within the generic HHH spec*

    So you acknowledge that HHH does not correctly simulate DD
    according to the definition of the x86 language.

    From what he writes, I get the feeling he thinks that HHH's
    result is /definitively/ correct, and that the x86 is at fault
    for producing the wrong result when executing DD directly.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From joes@21:1/5 to All on Mon Aug 11 17:51:31 2025
    Am Mon, 11 Aug 2025 12:49:22 -0500 schrieb olcott:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than
    redefining it.
    The categorical impossibility of finding a specific an error is this
    proof.
    You cannot show that DD emulated by HH according to the definition of
    the x86 language can possibly reach its own correctly emulated "ret"
    instruction because it cannot.
    That is the error.
    It is incorrect to call proven fact errors.
    The fact that HH can't reach DD's return is an error.

    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 18:59:48 2025
    On 11/08/2025 18:25, olcott wrote:
    Not at all. It is ridiculously stupid to require
    a simulating termination analyzer to simulate a
    non-terminating input to its non-existent completion.

    Indeed, because it's not possible. That's precisely the point. It
    can't be done. Non-terminating processes cannot be simulated to
    termination. If your job is to work out /purely by simulation
    whether they halt, your best bet is to take a guess and accept
    that you might get it wrong.

    And if you get it right, you got lucky.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 19:33:24 2025
    On 11/08/2025 18:48, olcott wrote:
    On 8/11/2025 11:42 AM, Richard Heathfield wrote:
    On 11/08/2025 17:29, olcott wrote:

    <snip>


    I have proven that DD correctly simulated by HHH

    No, you haven't. You have asserted that the simulation is
    correct, but we all know that it derives a different result
    from that produced by direct execution, and therefore we all
    know that the simulation is not correct.

    You can only fully know that your assumption is incorrect
    when you notice that no specific error exists.

    The specific error is that you get the wrong answer. This is an
    error so high, wide, thick, and deep that you cannot possibly get
    around or over it by pretending it's not there.

    Fortunately for you, it doesn't matter a damn, because it's not
    actually your real problem. A bit of debugging may well sort you
    out - who knows?

    No, the real problem, which is far higher and wider and thicker
    and deeper, is just behind it, and it's this: no matter what
    answer you get, it's the wrong answer.

    You cannot show that DD emulated by HH according
    to the definition of the x86 language can possibly
    reach its own correctly emulated "ret" instruction
    because it cannot.

    Of course it can't. You can't do the impossible.

    That's a fact that everybody here understands... except you,
    apparently.


    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 19:34:11 2025
    On 11/08/2025 18:49, olcott wrote:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than
    redefining
    it.

    The categorical impossibility of finding a specific an error
    is this
    proof.

    You cannot show that DD emulated by HH according to the
    definition of
    the x86 language can possibly reach its own correctly emulated
    "ret"
    instruction because it cannot.
    That is the error.


    It is incorrect to call proven fact errors.


    Corollary: it is incorrect to call errors proven fact.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 19:49:47 2025
    On 11/08/2025 19:06, olcott wrote:
    On 8/11/2025 12:59 PM, Richard Heathfield wrote:
    On 11/08/2025 18:25, olcott wrote:
    Not at all. It is ridiculously stupid to require
    a simulating termination analyzer to simulate a
    non-terminating input to its non-existent completion.

    Indeed, because it's not possible. That's precisely the point.
    It can't be done. Non-terminating processes cannot be simulated
    to termination. If your job is to work out /purely by
    simulation whether they halt, your best bet is to take a guess
    and accept that you might get it wrong.

    And if you get it right, you got lucky.


    If you bother to carefully examine this single page
    your key misconception will be fully addressed. https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    It doesn't, of course, because the misconception under which you
    are labouring is your own.

    This should clear it up for you:

    https://www.cs.virginia.edu/~robins/Turing_Paper_1936.pdf

    So much for arguing by URL.

    HHH(DD)==0 is correct when the behavior of DD
    is measured by DD correctly simulated by HHH.

    I'll give you this much - it's fine as far as it goes (despite
    getting the answer wrong, but let's skip over that, shall we?).

    But it doesn't... and *can't*... go far enough.


    Correctly is not completely. One not need to count
    to infinity to prove that they can count to ten.

    Indeed, but neither is incompletely correctly. One cannot count
    correctly up to ten by stopping at two and a half.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

    --- SoupGate-Win32 v1.05
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  • From Richard Heathfield@21:1/5 to olcott on Mon Aug 11 20:02:11 2025
    On 11/08/2025 19:40, olcott wrote:
    On 8/11/2025 1:33 PM, Richard Heathfield wrote:
    On 11/08/2025 18:48, olcott wrote:
    On 8/11/2025 11:42 AM, Richard Heathfield wrote:
    On 11/08/2025 17:29, olcott wrote:

    <snip>


    I have proven that DD correctly simulated by HHH

    No, you haven't. You have asserted that the simulation is
    correct, but we all know that it derives a different result
    from that produced by direct execution, and therefore we all
    know that the simulation is not correct.

    You can only fully know that your assumption is incorrect
    when you notice that no specific error exists.

    The specific error is that you get the wrong answer.
    It is incorrect to say it *is* a wrong answer until after
    a specific error in the basis of this answer is found.

    No, it isn't. Getting the wrong answer is more than enough
    justification for describing it as an error.

    Until that time it can be at most
    "seems like a wrong answer to me"

    Seems to me like it gets a different answer to the program it's
    simulating, ergo it's broken.

    extending beyond this is inaccurate thus untruthful.

    What do you call pretending it's fine when it clearly isn't?
    Disingenuous? A fib? A riddle?

    Why not call it what it is, which is Just Plain Bollocks.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

    --- SoupGate-Win32 v1.05
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  • From Richard Damon@21:1/5 to olcott on Mon Aug 11 20:40:15 2025
    On 8/11/25 10:33 AM, olcott wrote:
    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.


    The halting specification has always been wrong.

    You don't get to say that, and stay in the theory.


    You won't be able to understand why the halting
    specification has always been wrong until after
    you understand that the actual input to HHH(DD)
    specifies the non-halting behavior of recursive
    emulation.

    No, the problem is you don't understand the semantics of the input,
    because it seems to you, words don't need to mean what they mean.

    You left actauly being in the field when you said that, and are now in
    your own self-contradictory mostly undefined system that is just broken.

    Sorry. but you seem to just not understand the basics of Logic or Truth,
    which is what made you into a damned pathological liar.


    Apparently you don't understand what Claude AI said as you can only
    refer to it but cannot prove the same.

    Also
    https://philpapers.org/archive/OLCHPS.pdf

    As soon as you understand that the above page is
    entirely correct we can proceed to the last step
    of my proof.

    That paper is not entirely correct. It starts with an ill-posed question
    "What value should HHH(DD) correctly return?" where the exact meanings
    of "should" and "correctly" are not defined and cannot be inferred from
    the context.

    Later in the text there is the pharase "according to the specification"
    that does not identify any specification.

    In the "Answer" section there is the phrase "correctly identifies" where
    the norm for correctness is not identified. What is correct by one norm
    is incorrect by another norm. In this case the answer claimed "correct"
    is incorrect by the meanings of "termination analyzer" and "halting
    decider".

    That you hadn't noticed any error doesn't mean that there are none.

    Besidss, the text should have a title. And numbers in the text should
    be set with upper case digits.




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  • From Richard Damon@21:1/5 to olcott on Mon Aug 11 20:50:05 2025
    On 8/11/25 11:55 AM, olcott wrote:
    On 8/11/2025 10:46 AM, Richard Heathfield wrote:
    On 11/08/2025 16:21, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:

    <snip>


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be
    "wrong"?

    Good question.

    The halting problem specification requires a halt
    decider

    On the contrary, the halting problem demonstrates that such a decider
    cannot be built. Turing no more requires you to construct a halt
    decider than Zeno requires you to train a tortoise.

    <snip>


    Yes when you assume that I am wrong and then make
    sure to ignore what I said the false assumption
    cannot be shown to be false.

    Good job you used zero reasoning to affirm a false
    assumption. You know that this false assumption is
    true entirely on the basis of an incorrect guess.


    We don't "assume" you are wrong. we PROVE you are wrong by the proper
    meaning of the words you use that are defined in the system, even if you
    are trying to LIE by using them in another meaning that doesn't apply.

    Sorry, all you are doing is proving you are just a damned pathological liar.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Richard Damon@21:1/5 to olcott on Mon Aug 11 20:44:15 2025
    On 8/11/25 11:21 AM, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:
    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be "wrong"?

    The halting problem specification requires a halt
    decider to report on the behavior of the underlying
    Turing machine under the false assumption that input
    DD correctly simulated by halt decider HHH must have
    the same behavior as the directly executed DD().

    When I prove otherwise people here go on and on and
    on making sure to ignore this proof for months and
    months over years and years.

    You haven't proved otherwise, and you can't because defintions are
    definitions.

    At best you can prove that it leads to a contradiction in the system,
    like Russel did for the old set theory, now called Naive.

    All you have done is proven you get results you don't like, but that
    isn't a contradiction, it just shows you like errors.


    When they finally pay attention they say this proves
    that the simulation is wrong.

    When I prove that the simulation is correct they baselessly
    disagree. We fail to make progress because people will not
    look at the proof that the simulation is correct.


    No, you don't prove its "correct" as your "proof" doesn't follow the
    required rules of logic, but some grossly malformed version you created.

    ALl you are doing is showing how little you understand of what you are
    talking about, and just refuse to listen to reason, making you just a
    damned pathological lying idiot.

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  • From Richard Damon@21:1/5 to olcott on Mon Aug 11 20:48:49 2025
    On 8/11/25 11:32 AM, olcott wrote:
    On 8/11/2025 10:30 AM, dbush wrote:
    On 8/11/2025 11:21 AM, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:
    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required >>>>>> by the halting problem specification'.


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be
    "wrong"?

    The halting problem specification requires a halt
    decider to report on the behavior of the underlying
    Turing machine under the false assumption that input
    DD correctly simulated by halt decider HHH must have
    the same behavior as the directly executed DD().

    But DD is not correctly simulated by HHH as you have admitted on the
    record:


    *Anything that I said previously lacked this generic definition*

    Simulating Termination Analyzer HHH correctly simulates its input until:
    (a) Detects a non-terminating behavior pattern: abort simulation and
    return 0.
    (b) Simulated input reaches its simulated "return" statement: return 1.

    as its basis for analysis.


    which ignores the third option,

    (c) that HHH just continues simulating its input, possible forever,
    until one of the other things happen.

    And, if HHH actually DOES wait for one of the first two, that IS what
    happens.

    But if HHH decides to implement some pattern that it will see, then that pattern is also implemented in the DD that it is simulating, and thus
    the correct simulation (which now HHH doesn't do) will all see that
    incorrect pattern, abort its simulation, return 0 and DD will Halt,
    proving that the pattern wasn't a non-halting pattern.

    Sorry, your "proof" is just based on lies and bad logic as a basis for analysis.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Richard Damon@21:1/5 to olcott on Mon Aug 11 20:52:20 2025
    On 8/11/25 12:29 PM, olcott wrote:
    On 8/11/2025 11:18 AM, Richard Heathfield wrote:
    On 11/08/2025 16:55, olcott wrote:
    On 8/11/2025 10:46 AM, Richard Heathfield wrote:
    On 11/08/2025 16:21, olcott wrote:
    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:

    <snip>


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be
    "wrong"?

    Good question.

    The halting problem specification requires a halt
    decider

    On the contrary, the halting problem demonstrates that such a
    decider cannot be built. Turing no more requires you to construct a
    halt decider than Zeno requires you to train a tortoise.

    <snip>


    Yes when you assume that I am wrong

    It's not an assumption. I have a proof.

    and then make
    sure to ignore what I said

    When you say something worth reading, let me know. It hasn't happened
    yet.

    To date, all you've written are assertions masquerading as proofs -
    proofs that hold less water than a colander. You have an emulator that
    fails to emulate, a single-stepper that ignores 75% of what it's
    supposed to be single-stepping, a master's degree in rude buggeriness,
    and a complete inability to tell the difference between a thought
    experiment and an engineering project. You're the man who thought if
    only Icarus had used better glue.

    the false assumption
    cannot be shown to be false.

    Feel free to try. If you make a serious stab, I'll listen. But if you
    just say "first you must accept this list of falsehoods", I won't. You
    don't have a licence to demand that people accept bullshit in place of
    logic.

    Good job you used zero reasoning to affirm a false
    assumption. You know that this false assumption is
    true entirely on the basis of an incorrect guess.

    The only assumption I'm making is that you are right - Icarus can fly
    higher still, and a universal halt decider can be built. Having made
    that assumption, I can walk in Turing's footprints and derive a
    contradiction that proves the assumption to be false. No guessing
    involved.


    I have proven that DD correctly simulated by HHH
    cannot possibly reach its own "return" statement
    final halt state and you baselessly disagree.

    No, not is a universe where HHH uses that "fact" to declare its input non-halting, as there HHH doesn't do a correct simulation, and the
    correct simulation being look at was of a different program as input.

    Sorry, you are just proving you are doing logic by lies and misdefinition.


    All the while your disagreements remain baseless
    you really seem to be a troll. The only way to
    correct this is to provide a complete basis for
    your disagreement.


    No, your logic is baseless except for your own lies, which isn't worth
    the paper it isn't written on.

    --- SoupGate-Win32 v1.05
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  • From Mikko@21:1/5 to olcott on Tue Aug 12 12:02:55 2025
    On 2025-08-11 14:33:24 +0000, olcott said:

    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.

    The halting specification has always been wrong.

    Doesn't matter. It is what it is. You needn't talk about it if you
    don't want but you can't delete or change it.

    --
    Mikko

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  • From Mikko@21:1/5 to olcott on Tue Aug 12 12:04:08 2025
    On 2025-08-11 15:21:50 +0000, olcott said:

    On 8/11/2025 10:04 AM, dbush wrote:
    On 8/11/2025 10:33 AM, olcott wrote:
    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.


    The halting specification has always been wrong.

    In your own words, what does it mean for the specification to be "wrong"?

    The halting problem specification requires a halt
    decider to report on the behavior of the underlying
    Turing machine under the false assumption that input
    DD correctly simulated by halt decider HHH must have
    the same behavior as the directly executed DD().

    The halting problem specification says nothing about simulation.

    --
    Mikko

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  • From Fred. Zwarts@21:1/5 to All on Tue Aug 12 12:41:43 2025
    Op 11.aug.2025 om 19:57 schreef olcott:
    On 8/11/2025 12:51 PM, joes wrote:
    Am Mon, 11 Aug 2025 12:49:22 -0500 schrieb olcott:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than
    redefining it.
    The categorical impossibility of finding a specific an error is this >>>>> proof.
    You cannot show that DD emulated by HH according to the definition of >>>>> the x86 language can possibly reach its own correctly emulated "ret" >>>>> instruction because it cannot.
    That is the error.
    It is incorrect to call proven fact errors.

    The fact that HH can't reach DD's return is an error.


    The fact that DD correctly simulated by HHH cannot
    possibly reach the simulated "return" statement of
    DD is a direct result of DD calling HHH(DD) in recursive
    simulation.

    Which proves that a simulator cannot possibly be used for this purpose,
    because there are inputs for which it fails to reach the specified final
    halt state.


    It is like no one here has ever had a slight clue
    about what recursion is.


    You seem to fail to understand that many recursions are not infinite.
    You have built a simulator that forgets to analyse the conditional
    branch instructions during the recursion, so that a finite recursion is incorrectly seen as a non-termination behaviour pattern.

    You do not prove that the conditions for these branch instruction will
    never be met. You only prove that they are not met in the first two
    recursions.

    --- SoupGate-Win32 v1.05
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  • From Richard Damon@21:1/5 to olcott on Tue Aug 12 22:29:59 2025
    On 8/12/25 11:17 AM, olcott wrote:
    On 8/12/2025 4:37 AM, Chris M. Thomasson wrote:
    On 8/12/2025 2:02 AM, Mikko wrote:
    On 2025-08-11 14:33:24 +0000, olcott said:

    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.

    The halting specification has always been wrong.

    Doesn't matter. It is what it is. You needn't talk about it if you
    don't want but you can't delete or change it.


    your reason is most likely futile. shit happens?

    The halting problem itself has always been wrong
    when it requires a Turing machine to directly
    report on the behavior of another directly executed
    Turing machine because no Turing machine can take
    another directly executed Turing machine as an input.

    Proglems can't be "wrong" when the question asked has an answer.

    Note, the question is: Does the Machine described by this input halt.

    In this case, it does.


    The conventional proofs talk about a halt decider H
    reporting on the behavior of machine M on input P yet
    H is not given machine M it is only given machine
    description ⟨M⟩.

    And representations are sufficient, or you are admitting that arithmatic
    isn't computable, since Turing Machines can't be given "numbers" only representations of numbers.


    This assumes that the behavior of machine M on input P
    will be identical to the correct simulation of ⟨M⟩ on P.
    This is axiomatically true except in one specific case:

    Nope, it is DEFINITIONALY true.

    No exception.

    Can you show a sourcd for your claim, or is it just the POOP that you
    pull out of your ASS


    Machine M contains simulating halt decider H
    M.q0 ⟨M⟩ ⊢* M.H ⟨M⟩ ⟨M⟩ ⊢* M.qy
    M.q0 ⟨M⟩ ⊢* M.H ⟨M⟩ ⟨M⟩ ⊢* M.qn

    *Repeats until aborted proving non-halting*
    (a) M copies its input ⟨M⟩
    (b) M invokes M.H ⟨M⟩ ⟨M⟩
    (c) M.H simulates ⟨M⟩ ⟨M⟩

    then M.H ⟨M⟩ ⟨M⟩ transitions to M.qn
    causing M applied to ⟨M⟩ halt


    And the "Correct Simulation" of the input, per the semantic meaning of
    it, (which is the program it represents) continues after H stops looking
    by aborting its partial simulation, and it does exactly what H did, and
    goes to M.qn and Halts.


    Sorry, but you are just shown to be a stupid liar that doesn't know the
    meaning of words, and thinks semantic meaning isn't meaning and can be
    just changed.

    In other words, you logic is based on the right to lie, which shows the
    tyoe of logic you think is correct.

    --- SoupGate-Win32 v1.05
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  • From Mikko@21:1/5 to olcott on Wed Aug 13 11:13:49 2025
    On 2025-08-12 16:42:24 +0000, olcott said:

    On 8/12/2025 4:02 AM, Mikko wrote:
    On 2025-08-11 14:33:24 +0000, olcott said:

    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required
    by the halting problem specification'.

    The halting specification has always been wrong.

    Doesn't matter. It is what it is. You needn't talk about it if you
    don't want but you can't delete or change it.

    The halting specification ignores that the way that
    Turing machines actually work this is like trying to
    bake a cake in your washing machine.

    Of course. That need not be considered when evaluating the correctness
    of an answer to a halting question or the correctness of a candiate
    halt decider.

    --
    Mikko

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  • From Fred. Zwarts@21:1/5 to All on Wed Aug 13 11:03:17 2025
    Op 12.aug.2025 om 18:56 schreef olcott:
    On 8/12/2025 5:41 AM, Fred. Zwarts wrote:
    Op 11.aug.2025 om 19:57 schreef olcott:
    On 8/11/2025 12:51 PM, joes wrote:
    Am Mon, 11 Aug 2025 12:49:22 -0500 schrieb olcott:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than
    redefining it.
    The categorical impossibility of finding a specific an error is this >>>>>>> proof.
    You cannot show that DD emulated by HH according to the
    definition of
    the x86 language can possibly reach its own correctly emulated "ret" >>>>>>> instruction because it cannot.
    That is the error.
    It is incorrect to call proven fact errors.

    The fact that HH can't reach DD's return is an error.


    The fact that DD correctly simulated by HHH cannot
    possibly reach the simulated "return" statement of
    DD is a direct result of DD calling HHH(DD) in recursive
    simulation.

    Which proves that

    The actual behavior of the actual input is not-halting.
    The actual behavior of a non-input does not contradict
    this because halt deciders are not accountable for the
    behavior of non-inputs.


    As usual incorrect claims without evidence.

    It proves that a simulator is not the right tool for this purpose,
    because there are inputs for which it fails to reach the specified final
    halt state. Using a simulator to analyse the input causes recursive
    simulation, which the simulator cannot handle correctly.
    Correct simulations of exactly the same input show that the final halt
    state can be reached.
    A correct simulation should acknowledge that and not assume a
    hypothetical non-input that does not halt.

    You seem to fail to understand that many recursions are not infinite.
    You have built a simulator that forgets to analyse the conditional
    branch instructions during the recursion, so that a finite recursion is incorrectly seen as a non-termination behaviour pattern.

    You do not prove that the conditions for these branch instruction will
    never be met. You only prove that they are not met in the first two
    recursions.

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  • From Richard Heathfield@21:1/5 to olcott on Wed Aug 13 17:22:05 2025
    On 13/08/2025 16:58, olcott wrote:
    It is common knowledge that Turing machines do
    not take other Turing machines as inputs.

    Are you gonna fix Wikipedia, or shall I?

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Heathfield@21:1/5 to olcott on Wed Aug 13 19:31:40 2025
    On 13/08/2025 18:10, olcott wrote:
    On 8/13/2025 11:22 AM, Richard Heathfield wrote:
    On 13/08/2025 16:58, olcott wrote:
    It is common knowledge that Turing machines do
    not take other Turing machines as inputs.

    Are you gonna fix Wikipedia, or shall I?


    One of my two most credible sources must understand
    what I say before such a fix can be made.


    Good luck persuading the Wiki gang. They won't argue with you for
    22 years; they'll just ban you as soon as you undo their first undo.


    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From Richard Damon@21:1/5 to olcott on Wed Aug 13 22:23:44 2025
    On 8/13/25 11:58 AM, olcott wrote:
    On 8/13/2025 4:03 AM, Fred. Zwarts wrote:
    Op 12.aug.2025 om 18:56 schreef olcott:
    On 8/12/2025 5:41 AM, Fred. Zwarts wrote:
    Op 11.aug.2025 om 19:57 schreef olcott:
    On 8/11/2025 12:51 PM, joes wrote:
    Am Mon, 11 Aug 2025 12:49:22 -0500 schrieb olcott:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than >>>>>>>>>> redefining it.
    The categorical impossibility of finding a specific an error is >>>>>>>>> this
    proof.
    You cannot show that DD emulated by HH according to the
    definition of
    the x86 language can possibly reach its own correctly emulated >>>>>>>>> "ret"
    instruction because it cannot.
    That is the error.
    It is incorrect to call proven fact errors.

    The fact that HH can't reach DD's return is an error.


    The fact that DD correctly simulated by HHH cannot
    possibly reach the simulated "return" statement of
    DD is a direct result of DD calling HHH(DD) in recursive
    simulation.

    Which proves that

    The actual behavior of the actual input is not-halting.
    The actual behavior of a non-input does not contradict
    this because halt deciders are not accountable for the
    behavior of non-inputs.


    As usual incorrect claims without evidence.


    It is common knowledge that Turing machines do
    not take other Turing machines as inputs. That
    you did not know this is not any lack of evidence.

    When HHH(DD) is executed that this begins simulating
    DD that calls HHH(DD) that begins simulating DD that
    calls HHH(DD) again.

    Is proven by the semantics of the C programming
    language.

    It proves that a simulator is not the right tool for this purpose,
    because there are inputs for which it fails to reach the specified
    final halt state. Using a simulator to analyse the input causes
    recursive simulation, which the simulator cannot handle correctly.
    Correct simulations of exactly the same input show that the final halt
    state can be reached.
    A correct simulation should acknowledge that and not assume a
    hypothetical non-input that does not halt.

    You seem to fail to understand that many recursions are not infinite.

    Stopping running and halting are not the same thing.

    When N instructions of DD are correctly simulated
    by any HHH this correctly simulated DD cannot possibly
    reach its own final halt state because it calls HHH(DD)
    in recursive simulation.

    But not reaching a final state in just N steps, isn't non-halting,

    The behavior of the input continues past that point, and it WILL reach a
    final state, since it has the same HHH as part of it, that will do the
    same thing,


    You have built a simulator that forgets to analyse the conditional
    branch instructions during the recursion, so that a finite recursion
    is incorrectly seen as a non-termination behaviour pattern.


    If we were looking at whether or not DD simulated
    by HHH ever stops running you would be correct.
    We are not looking at that.

    But we aren't, we were looking at if the program represented by the
    input halts.

    All you are doing is ADMITTING that you have been lying about working on
    the halting problem in the first place.

    Why should we care what a liar wants to do?


    You do not prove that the conditions for these branch instruction will
    never be met. You only prove that they are not met in the first two
    recursions.



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  • From Richard Damon@21:1/5 to Richard Heathfield on Wed Aug 13 22:26:15 2025
    On 8/13/25 2:31 PM, Richard Heathfield wrote:
    On 13/08/2025 18:10, olcott wrote:
    On 8/13/2025 11:22 AM, Richard Heathfield wrote:
    On 13/08/2025 16:58, olcott wrote:
    It is common knowledge that Turing machines do
    not take other Turing machines as inputs.

    Are you gonna fix Wikipedia, or shall I?


    One of my two most credible sources must understand
    what I say before such a fix can be made.


    Good luck persuading the Wiki gang. They won't argue with you for 22
    years; they'll just ban you as soon as you undo their first undo.



    If he hasn't already been ban for other edits he has done.

    I know I reported one such lie a few years ago, I don't know if they did anything about it.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Richard Damon@21:1/5 to olcott on Wed Aug 13 22:29:40 2025
    On 8/13/25 11:32 AM, olcott wrote:
    On 8/13/2025 3:13 AM, Mikko wrote:
    On 2025-08-12 16:42:24 +0000, olcott said:

    On 8/12/2025 4:02 AM, Mikko wrote:
    On 2025-08-11 14:33:24 +0000, olcott said:

    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required >>>>>> by the halting problem specification'.

    The halting specification has always been wrong.

    Doesn't matter. It is what it is. You needn't talk about it if you
    don't want but you can't delete or change it.

    The halting specification ignores that the way that
    Turing machines actually work this is like trying to
    bake a cake in your washing machine.

    Of course. That need not be considered when evaluating the correctness
    of an answer to a halting question or the correctness of a candiate
    halt decider.


    Likewise: "What time is it (yes or no)?
    is not Turing computable.

    Does your input specify a sequence of move that halts?
    Is proven for HHH(DD).


    And the answer is YES, as your HHH(DD) returns 0, so DD will halt.

    Since the semantic meaning of an input to a halt decider is the Turning
    Machine it is supposed to be representing. If it doesn't mean that, you
    gave the wrong input.

    So, you are just admitting that either you HHH tries to redefine a well
    defined input, or you gave the wrong input to it.

    In truth, you did both, since you try to imply that the "input" to HHH
    for DD only has the bytes of the C funciton DD, instead of all the
    memory with code that it uses.

    And HHH doesn't correctly interprete the call HHH the second time it
    sees it, when it aborts.

    Sorry, you are just showing you are just a liar.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Fred. Zwarts@21:1/5 to All on Thu Aug 14 10:54:14 2025
    Op 13.aug.2025 om 17:58 schreef olcott:
    On 8/13/2025 4:03 AM, Fred. Zwarts wrote:
    Op 12.aug.2025 om 18:56 schreef olcott:
    On 8/12/2025 5:41 AM, Fred. Zwarts wrote:
    Op 11.aug.2025 om 19:57 schreef olcott:
    On 8/11/2025 12:51 PM, joes wrote:
    Am Mon, 11 Aug 2025 12:49:22 -0500 schrieb olcott:
    On 8/11/2025 11:35 AM, joes wrote:
    Am Mon, 11 Aug 2025 11:00:18 -0500 schrieb olcott:
    On 8/11/2025 10:49 AM, joes wrote:

    You have no proof that the simulation is correct other than >>>>>>>>>> redefining it.
    The categorical impossibility of finding a specific an error is >>>>>>>>> this
    proof.
    You cannot show that DD emulated by HH according to the
    definition of
    the x86 language can possibly reach its own correctly emulated >>>>>>>>> "ret"
    instruction because it cannot.
    That is the error.
    It is incorrect to call proven fact errors.

    The fact that HH can't reach DD's return is an error.


    The fact that DD correctly simulated by HHH cannot
    possibly reach the simulated "return" statement of
    DD is a direct result of DD calling HHH(DD) in recursive
    simulation.

    Which proves that

    The actual behavior of the actual input is not-halting.
    The actual behavior of a non-input does not contradict
    this because halt deciders are not accountable for the
    behavior of non-inputs.


    As usual incorrect claims without evidence.


    It is common knowledge that Turing machines do
    not take other Turing machines as inputs. That
    you did not know this is not any lack of evidence.

    As usual irrelevant claims.
    It is common knowledge that Turing Machines can take the description of
    any other Turing machine as input. That you do not understand the
    difference between a Turing Machine and its description makes this
    statement irrelevant.
    It is also common knowledge that a Turing Machine cannot determine the
    halting behaviour of all possible inputs.


    When HHH(DD) is executed that this begins simulating
    DD that calls HHH(DD) that begins simulating DD that
    calls HHH(DD) again.

    Indicating that simulation is not the right tool for this input, because
    it creates a recursion that cannot be handled by simulation.


    Is proven by the semantics of the C programming
    language.

    More support that simulation is not the right tool.


    It proves that a simulator is not the right tool for this purpose,
    because there are inputs for which it fails to reach the specified
    final halt state. Using a simulator to analyse the input causes
    recursive simulation, which the simulator cannot handle correctly.
    Correct simulations of exactly the same input show that the final halt
    state can be reached.
    A correct simulation should acknowledge that and not assume a
    hypothetical non-input that does not halt.

    You seem to fail to understand that many recursions are not infinite.

    Stopping running and halting are not the same thing.

    Aborting a simulation is not a proof for non-halting behaviour of the input.


    When N instructions of DD are correctly simulated
    by any HHH this correctly simulated DD cannot possibly
    reach its own final halt state because it calls HHH(DD)
    in recursive simulation.

    Indeed. We agree that HHH fails, where other simulators show that the
    finite halt state will be reached after simulating M instructions for
    the exact same input
    But, M > N, so HHH fails.
    Creating another HHH that simulates M instructions, shows that it can
    reach the final halt state of exactly the same input.
    But then we can create another new input for which the new HHH will
    fail, as well.


    You have built a simulator that forgets to analyse the conditional
    branch instructions during the recursion, so that a finite recursion
    is incorrectly seen as a non-termination behaviour pattern.


    If we were looking at whether or not DD simulated
    by HHH ever stops running you would be correct.
    We are not looking at that.

    We are looking at whether HHH is able te recognise the final halt state specified in the input. Up to know you could not present a HHH that
    could do that. Each HHH you present fails to reach the final halt state.
    We are not looking at whether we can correct HHH to do a correct
    simulation, because it is clear that it cannot do that.
    Whatever you try, we can always construct a DD for which HHH fails to
    reach the specified final halt instruction.


    You do not prove that the conditions for these branch instruction will
    never be met. You only prove that they are not met in the first two
    recursions.



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    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Mikko@21:1/5 to olcott on Thu Aug 14 13:00:12 2025
    On 2025-08-13 15:32:16 +0000, olcott said:

    On 8/13/2025 3:13 AM, Mikko wrote:
    On 2025-08-12 16:42:24 +0000, olcott said:

    On 8/12/2025 4:02 AM, Mikko wrote:
    On 2025-08-11 14:33:24 +0000, olcott said:

    On 8/11/2025 1:44 AM, Mikko wrote:
    On 2025-08-10 14:15:12 +0000, olcott said:

    On 8/10/2025 2:58 AM, Mikko wrote:

    Claude AI proved why HHH(DD)==0 is correct in terms that
    any expert C programmer can understand.
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

    Irrelevant as long as the meaning of "correct" is not 'as required >>>>>> by the halting problem specification'.

    The halting specification has always been wrong.

    Doesn't matter. It is what it is. You needn't talk about it if you
    don't want but you can't delete or change it.

    The halting specification ignores that the way that
    Turing machines actually work this is like trying to
    bake a cake in your washing machine.

    Of course. That need not be considered when evaluating the correctness
    of an answer to a halting question or the correctness of a candiate
    halt decider.

    Likewise: "What time is it (yes or no)?
    is not Turing computable.

    The "Likewise" is false but the rest is true.

    Does your input specify a sequence of move that halts?
    Is proven for HHH(DD).

    No, the question is not proven and cannot be.
    But it is an almost valid question ("move" should be "moves") that
    has an answer.

    --
    Mikko

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