How can i write this function Cprod (Cartesian Product) simply?

(writing this out: itertools.product([0, 1], repeat=N )

The value can be a list or a Tuple.

cprod([0, 1], 1) => ((0) (1))

cprod([0, 1], 2) => ((0,0) (0,1) (1,0) (1,1))



This works:

def cprod(x, c):
if c==1: return [[i] for i in x]
Sub= cprod(x, c-1)
return [i for F in x for i in [[F]+R for R in Sub]]


---------- Is there another way to write [F]+R ???

Other ways to improve it?

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On 22/05/24 07:14, HenHanna via Python-list wrote:

How can i write this function Cprod (Cartesian Product) simply?

                (writing this out: itertools.product([0, 1], repeat=N )

The value can be a list or a Tuple.

                cprod([0, 1], 1) => ((0) (1))

                cprod([0, 1], 2) => ((0,0) (0,1) (1,0) (1,1))

This works:

   def cprod(x, c):
        if c==1: return [[i] for i in x]
        Sub= cprod(x, c-1)
        return [i  for F in x   for i in [[F]+R for R in Sub]]

---------- Is there another way to write [F]+R ???

               Other ways to improve it?

https://python.readthedocs.io/en/stable/library/itertools.html#itertools.product

--
Regards,
=dn

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dn wrote:

On 22/05/24 07:14, HenHanna via Python-list wrote:

How can i write this function Cprod (Cartesian Product) simply?

                (writing this out: itertools.product([0, 1], repeat=N
)

The value can be a list or a Tuple.

                cprod([0, 1], 1) => ((0) (1))

                cprod([0, 1], 2) => ((0,0) (0,1) (1,0) (1,1))



This works:

   def cprod(x, c):
        if c==1: return [[i] for i in x]
        Sub= cprod(x, c-1)
        return [i  for F in x   for i in [[F]+R for R in Sub]]


---------- Is there another way to write [F]+R ???

               Other ways to improve it?

https://python.readthedocs.io/en/stable/library/itertools.html#itertools.product
Regards, =dn

Thank you... That code looks elegant... I'll study it.

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