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  • Re: incr result with non-var argument

    From Oleg Nemanov@21:1/5 to All on Fri Apr 22 04:48:25 2022
    пятница, 22 апреля 2022 г. в 14:45:02 UTC+3, Oleg Nemanov:
    Hi, all.

    Why incr return a sequence of numbers in this case:

    % set a [dict create k 22]
    k 22
    % incr [dict get $a k]
    1
    % incr [dict get $a k]
    2
    % incr [dict get $a k]
    3
    % incr [dict get $a k]
    4
    % puts $a
    k 22

    :-D I understood. Because incr increment a variable with name '22'.

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  • From Oleg Nemanov@21:1/5 to All on Fri Apr 22 04:44:59 2022
    Hi, all.

    Why incr return a sequence of numbers in this case:

    % set a [dict create k 22]
    k 22
    % incr [dict get $a k]
    1
    % incr [dict get $a k]
    2
    % incr [dict get $a k]
    3
    % incr [dict get $a k]
    4
    % puts $a
    k 22

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Alan Grunwald@21:1/5 to Oleg Nemanov on Fri Apr 22 19:57:29 2022
    On 22/04/2022 12:44, Oleg Nemanov wrote:
    Hi, all.

    Why incr return a sequence of numbers in this case:

    % set a [dict create k 22]
    k 22
    % incr [dict get $a k]
    1
    % incr [dict get $a k]
    2
    % incr [dict get $a k]
    3
    % incr [dict get $a k]
    4
    % puts $a
    k 22

    Evaluate

    set 22

    Does that help explain what's happening?

    Alan

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Alan Grunwald@21:1/5 to Alan Grunwald on Fri Apr 22 20:00:56 2022
    On 22/04/2022 19:57, Alan Grunwald wrote:
    On 22/04/2022 12:44, Oleg Nemanov wrote:
    Hi, all.

    Why incr return a sequence of numbers in this case:

    % set a [dict create k 22]
    k 22
    % incr [dict get $a k]
    1
    % incr [dict get $a k]
    2
    % incr [dict get $a k]
    3
    % incr [dict get $a k]
    4
    % puts $a
    k 22

    Evaluate

    set 22

    Does that help explain what's happening?

    Alan

    Sorry. I must remember to read the whole thread before I follow up.

    Alan

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