XPost: comp.theory, sci.logic, sci.math
On 9/30/2021 6:14 PM, Ben Bacarisse wrote:
olcott <[email protected]> writes:
On 9/30/2021 11:35 AM, Ben Bacarisse wrote:
olcott <[email protected]> writes:
On 9/29/2021 9:42 PM, Ben Bacarisse wrote:
olcott <[email protected]> writes:
H(<Ĥ>,<Ĥ>) ⊢* H.qy as I just said
H(<Ĥ>,<Ĥ>) ⊢* H.qy as I just said
H(<Ĥ>,<Ĥ>) ⊢* H.qy as I just said
H(<Ĥ>,<Ĥ>) ⊢* H.qy as I just said
H(<Ĥ>,<Ĥ>) ⊢* H.qy as I just said
But you previously also said that H(<Ĥ>,<Ĥ>) ⊢* H.qn. You can't get mad
because people believe what you write!
Now I need to know how much of the post where you said that your new >>>>> basis for halting gives H(<Ĥ>,<Ĥ>) ⊢* H.qn was /also/ wrong. All of it?
It formed what appeared to be your entire justification for having
"solved" the halting problem. Here is the whole thing:
| My current proof simply shows exactly how the exact Peter Linz H would >>>>> | correctly decide not halting on the exact Peter Linz Ĥ.
|
| This definition of halting circumvents the pathological self-reference >>>>> | error for every simulating halt decider:
|
| An input is decided to be halting only if its simulation never needs >>>>> | to be stopped by any simulating halt decider anywhere in its entire >>>>> | invocation chain.
|
| On that basis:
| Ĥ(<Ĥ>) ⊢* Ĥ.qn
| H(<Ĥ>,<Ĥ>) ⊢* H.qn
It seems a little shady that you don't cut-and-paste it with the time
and date stamp as I ALWAYS do.
It's Message-ID: <[email protected]>
Are you accusing me of misquoting you?
I am accusing you of not providing proper support for your assertions.
Good. So you do agree that you said it?
A cut-and-paste of my actual question that includes the time and date
stamp is the standard that I established for myself.
I post a message ID if anyone is having trouble finding a post.
You, presumably, knew all along that you have redefined what halting
means so that H and H^ are no longer like Linz's H and H^. You,
presumably, knew that with your definition H can reject a halting computation. After all, that's what everyone has been objecting to for
the last few years. You can't have only just noticed that this is what people have been telling you.
If the above is an accurate quote (which has not been properly
established) then--->H(<Ĥ>,<Ĥ>) ⊢* H.qn is a typographical error.
This is an appallingly dishonest claim. There is no possibility it is a typo. Why would you even try to pretend that it is? You say the same
thing again in another post
H(<Ĥ>,<Ĥ>) ⊢* H.qn
Message-ID: <[email protected]>
and again using words this time
H applied to input (Ĥ, Ĥ) transitions to H.qn
Message-ID: <[email protected]>
and again in words
H(<Ĥ>,<Ĥ>) must abort the simulation of its input ∴ this input <is>
correctly decided as non-halting.
Message-ID: <[email protected]>
and again using a slightly different notion here
H.q0 ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* H.qn
Message-ID: <[email protected]>
And then there is the fact that you've been saying exactly this in other
ways for months:
"Halts(Confound_Halts, Confound_Halts) returns false."
Message-ID: <[email protected]>
and
"The input to Halts is only finite because..."
Message-ID: <[email protected]>
And H(H_Hat, H_Hat) == false though H_Hat(H_Hat) halts. Post after post explaining why H(H_Hat, H_Hat) == 0 with H_Hat(H_Hat) halting might
/seem/ wrong but is in fact correct because of how you define halting.
No, it is not a typo. You are lying. You meant what you wrote, and
people have been addressing what you now pretend is a typo for months.
The scale of the dishonesty takes my breath away.
I could explain why you are wrong to say
Ĥ(<Ĥ>) ⊢* Ĥ.qn and H(<Ĥ>,<Ĥ>) ⊢* H.qy
but what's the point? You'll just claim that this was also a typo in a
few months time. You can keep this up forever if you have no attachment
to honesty or the truth.
You quoted me from five months ago my view has changed.
Here is my view now.
If you want to try to form an actual rebuttal and not just some form of
the strawman error that looks like a rebuttal to gullible fools that are
hardly paying attention you must address the following POINT-BY-POINT.
(A) Ĥ(<Ĥ>) ⊢* Ĥ.qn
(B) Ĥ.qx(<Ĥ>,<Ĥ>) ⊢* H.qn
Your whole basis of rebuttal from the beginning has been that (B) must
be wrong because it disagrees with the actual behavior of (A).
Now that I know that H(<Ĥ>,<Ĥ>) ⊢* H.qy
I have directly contradicted the Linz conclusion.
The contradiction tells us that our assumption
of the existence of H, and hence the assumption
of the decidability of the halting problem, must
be false. (Linz:1990:320)
https://www.liarparadox.org/Peter_Linz_HP(Pages_315-320).pdf
Linz, Peter 1990. An Introduction to Formal Languages and Automata. Lexington/Toronto: D. C. Heath and Company. (318-320)
Ĥ.qx(<Ĥ>,<Ĥ>) ⊢* H.qn is correct because the simulation of <Ĥ> applied
to <Ĥ> never reaches any final state whether or not the simulating halt decider at Ĥ.qx aborts its simulation of this input.
You can dishonestly call this another different halting problem yet you
know damn well it is the original halting problem.
That a computation never reaches its final state when this computation
is allowed to continue unabated is the very conventional definition of
not halting.
I don't know the proper way to say this because the definition of a
computation is restricted to sequence of steps that halts. This makes
non halting computations a contradiction in terms.
--
Copyright 2021 Pete Olcott
"Great spirits have always encountered violent opposition from mediocre
minds." Einstein
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